IONIZING RADIATION MCQs FOR EXAM | RRB, SSC, AIIMS | Radiology Notes

IONIZING RADIATION MCQs FOR RADIOGRAPHER EXAM PREPARATION



1. Which statement about the differences between medical imaging using X-rays and a nuclear medicine scan using gamma rays is correct?

A. An X-ray procedure leaves the patient with residual radioactivity while nuclear medicine does not.

B. A gamma ray source can be switched off after which no gamma radiation is produced while an X-ray source will continue to produce radiation until the source decays.

C. X-rays produce an image of internal anatomy while a nuclear medicine scan provides information about the functioning of an organ or tissue.

D. A beam of gamma rays is fired at the patient and detected on the other side, while X-rays are produced by the nucleus of a radionuclide incorporated in the patient’s body.

 

Answer is C: X-rays that pass through the body without being absorbed by the body are used to produce an image of internal structure. In nuclear medicine, a radioactive material is incorporated into the body, travels to certain organs from where a gamma ray is emitted. If physiology is altered sufficiently to affect the way the radioactive material moves about the body, the resulting image provides information about how much alteration there has been.

 

2. Conventional radiography—such as a chest X-ray (CXR)—differs from computed

tomography (CT) in what respect?

A. CT produces an image of all internal anatomy while in CXR, overlying anatomical structures obscure the view of underlying structures.

B. In CT the patient is left with some residual radioactivity, but not with CXR.

C. CT produces a lower absorbed dose of radiation to the patient than does a CXR.

D. CT involves the use of ultrasound while a CXR results from X-rays.

 

Answer is A: CT mages are unobstructed by the “shadow” of overlying structures.

 

3. Which of the following imaging modalities does NOT involve the use of “ionizing radiation”?

A. Mammography

B. Ultrasound

C. A scintigram using technetium

D. A chest X-ray

 

Answer is B: Ultrasound produces an oscillation in the particles of the body, but does not use ionising electromagnetic radiation.

 

4. When inspecting an X-ray image, the order of densities from blackest to whitest is:

A. Bone, water, fat, air

B. Air, fat, water, bone

C. Air, water, fat, bone

D. Bone, air, water, fat

 

Answer is B: The blackest part on an X-ray image is air, while the whitest is bone.

 

5. Which of the following imaging modalities uses X-rays?

A. Computed tomography (CT)

B. Single-photon emission computed tomography (SPECT)

C. Positron emission tomography (PET)

D. Nuclear medicine scan (scintigram)

 

Answer is A: CT machines generate X-rays. The others are all nuclear medicine procedures.

 

6. Radiation which is “ionising” includes which of the following?

A. X-rays and gamma rays

B. Infrared radiation

C. Radiation emitted by mobile phones

D. Microwaves

 

Answer is A: The other three choices, while also being forms of electromagnetic radiation, do not utilise energies that are sufficient to remove electrons from their atoms.

 

7. The lead aprons that are used for the protection of staff in diagnostic radiography procedures do not provide protection against the ionising radiation used in nuclear medicine or radiotherapy. Why is this? Because:

A. Charged particles are much easier to stop (are less penetrating) than photons are.

B. Gamma rays are more penetrating than x-rays even if both have the same energy.

C. Such aprons do not cover the arms, feet, head and neck.

D. The shielding provided by aprons is not sufficient to stop photons with energies above 100 keV.

 

Answer is D: Diagnostic radiography uses X-rays with an average energy of 70 keV or less, which can be stopped by relatively thin amounts of lead (or leadlike) material. In order to stop the gamma rays used in nuclear medicine imaging, the thickness of the “aprons” would make them prohibitively heavy to wear.

 

8. When compared to visible light, which is not very penetrating, why can radiation such as X-rays and gamma rays pass right through the human body? Because:

A. The density of the human body is relatively low.

B. They have no mass and no charge.

C. Atoms in the body are mostly empty space.

D. They have very high energy.


Answer is D: X- and gamma rays are high energy radiation, which means high frequency, which means short wavelength, which means that many of the photons will pass through the body without interacting with any atoms. The other three choices do not distinguish between different types of radiation.

 

9. Which of the following is true?

A. A patient exposed to diagnostic X-rays will emit X-rays for a short time after the procedure.

B. A cancer patient treated with a megavoltage beam of X-rays will emit X-rays for a short time after the treatment.

C. For a short time after having a bone scan using the radionuclide technetium-99m, the patient will emit gamma rays.

D. The human body does not contain any radioactive material unless it has been exposed to man-made radioactive material.

 

Answer is C: A bone scan (any nuclear medicine scan) involves taking some radioactive materials into the body which then emits gamma rays to be detected outside the body. The body takes some time to excrete the material (and much of it decays) so until that happens, the body is more radioactive than is usually the case.

 

10. What does the term ionising radiation refer to?

A. The radiation that is emitted by ionised atoms

B. That part of the electromagnetic spectrum with wavelengths less than 300 nm which has enough energy to produce ions

C. Alpha, beta and gamma rays spontaneously emitted from radionuclides

D. Radiation with enough energy to produce ionisation in the material which absorbs it

 

Answer is D: If the radiation produces ions when it interacts with any substance, then it is ionising radiation. Choice B is true but does not include particulate radiation. Choice C is true but does not include X-rays or cosmic rays.

 

11. Which of the following is a correct use of the unit known as the “electron volt” (eV)? 

A. One electron volt is the amount of radioactivity that results in one disintegration per second.

B. Radiopharmaceuticals contain gamma photon emitting radionuclides whose energy is usually in the range 100–250 keV.

C. One electron volt is equal to 1.9 × 1016 J of energy.

D. A photon of visible light has energy of about 1.5 MeV.

 

Answer is B: eV is a unit of energy (not radioactivity). It is equal to 1.9 × 1016 J of energy. Visible photons have energy of 1.5 eV or less.

 

12. Which one of the statements about the penetrating ability of radiation is true?

A. 750 keV gamma rays are more penetrating than 750 keV X-rays.

B. 140 keV gamma rays are more penetrating than 60 keV X-rays.

C. 2 MeV beta rays (electrons) are more penetrating than 1 MeV gamma rays.

D. 1 MeV gamma rays are more penetrating than 2 MeV X-rays.

 

Answer is B: Gamma rays and X-rays are indistinguishable, once they have travelled away from their site of production. So a 140 keV gamma or X-ray is more penetrating than a lower energy one.

 

13. What may the term “ionising radiation” be applied to?

A. All electromagnetic radiation

B. Radiation that produces ions when it interacts with matter

C. Infrared radiation

D. Radiation that is emitted by ions

 

Answer is B: The production of ions (i.e. removal of electrons from an atom) is the sign of ionising radiation. Such a change in the medium through which radiation passes is significant.

 

14. What does it mean when an X-ray tube is operated at an accelerating voltage of 120 kV?

 A. The maximum energy that an X-ray photon can have will be 120 keV.

B. The characteristic X-rays will have energy 120 keV.

C. All of the X-ray photons will have an energy of 120 keV.

D. The X-ray beam will contain photons with every energy from 0 keV up to 120 keV.

 

Answer is A: X-rays are emitted from the tube with a range of energies (a spectrum) which will range from mid-teens to low 20s of keV (depending on the amount of “filtration” that the photons pass through) up to the maximum value which will equal the accelerating voltage.

 

15. Why do some X-ray photons pass through the human body without deflection? Because:

A. Carbon, hydrogen and oxygen atoms are transparent to X-rays.

B. The energy of diagnostic X-rays is too low to produce interactions

C. The wavelength of X-rays is too long to interact with an object with the dimensions of the human body.

D. The interior of atoms is mostly empty space.

 

Answer is D: Apart from the positions where electrons and the nuclei are located, the rest of the body is empty space through which photons can travel unimpeded. They will interact only if they “hit” these subatomic particles. The other answers contain errors.

 

16. How will increasing the filtration of an X-ray beam reduce the intensity of the X-ray spectrum?

A. Equally at all frequencies

B. More at lower frequencies than at higher frequencies

C. More at higher frequencies than at lower frequencies

D. Only at lower frequencies

 

Answer is B: Lower frequency radiation is less penetrating than higher frequency radiation, so the low frequency are preferentially absorbed compared to high frequency radiation.

 

17. What is the difference between X-rays and gamma rays? 

A. X-rays are ionising radiation and gamma rays are not.

B. Gamma rays have higher energies than X-rays.

C. Gamma rays can be turned off by switching the power supply off.

D. X-rays are produced in an electrical machine whereas gamma rays emerge from an atomic nucleus.

 

Answer is D: Apart from the difference in how they are produced, X-rays and gamma rays are the same phenomenon.

 

18. To what energy can an X-ray tube that is operated at 110 kV accelerate electrons?

A. 110 eV

B. 110 keV

C. 110 J

D. 110,000 keV

 

Answer is B: An electron volt is the amount of energy gained by an electron when it is accelerated by a potential difference of 1 V. 110 keV is the amount of energy gained by an electron when it is accelerated by a potential difference of 110 kV.

 

19. What is the purpose of adding filtration to an X-ray beam? To:

A. Prevent high-energy photons entering the patient

B. Increase the mean energy of the beam

C. Decrease the scattered radiation

D. Increase the ratio of low energy photons to high energy photons

 

Answer is B: X-rays are produced in an X-ray tube with a range of energies. Filtration will absorb the lowest energy photons more than higher energy ones. This will result in the average energy of the remaining spectrum increasing.

 

20. Consider the “inverse square law”. Compared to being 1 m from a point X-ray

source, what will be the photon flux at a distance of 4 m from the source?

A. Sixteen times as great

B. Eight times as great

C. One eighth as great

D. One sixteenth as great

 

Answer is D: “Inverse square” means at double the distance, the flux will be one half squared of the original flux (½)2 = ¼. At 4× the distance, the flux will be (¼)2 = 1/16.

 

21. What is the purpose of an intensifying screen?

A. It converts a small number of X-ray photons into a large number of visible light photons.

B. It converts low energy X-ray photons into high energy visible light photons.

C. It improves the absorption efficiency of X-rays.

D. It protects the radiologist’s eyes from the damage that would be caused by X-rays.

 

Answer is A: It converts X-rays (which have high energies but are invisible) into visible light photons. Because visible light photons have low energy, an X-ray photon can be made to produce lots of them.

 

22. One difference between the X-radiation in the primary beam and the scattered radiation is that:

A. Photons in the primary beam degrade contrast in radiographic images.

B. Scattered radiation is more penetrating than the primary beam.

C. Scattered radiation may be absorbed in the imager.

D. Scattered radiation is travelling at an angle to the main beam.

 

Answer is D: “Scattered” radiation has interacted with an atom in the medium so is diverted from the direction of the primary beam.

 

23. The advantage of computed tomography (CT) over conventional radiography is: 

A. CT delivers lower doses than conventional radiography.

B. CT images are faster to acquire than conventional radiographs

C. CT produces a cross-sectional image that is not obscured by overlying anatomical structures.

D. CT projects a 3D structure onto a 2D image.

 

Answer is C: It is the ability to image internal structures without having them partially obscured by the tissue on either side as is the case for “conventional” radiography that makes CT such a useful diagnostic tool. (Also there is no need to cut the person open to see what is inside!)

 

24. The contrast of a CT image displayed on a monitor may be increased by:

A. Increasing the window width

B. Increasing the window level

C. Decreasing the window width

D. Decreasing the window level

 

Answer is C: Decreasing the width of the “window” means restricting the range of grey scale displayed on the monitor screen (0–255), to a more limited range of the available Hounsfield numbers (1000 for air to 3000 for dense bone). A lung window may be 1250 to +250; a soft tissue window may be 160 to +240; a bone window may be 650 to +1350.


25. Which one of the following beams is the most penetrating?

A. 2 MeV gamma rays

B. 2 MeV X-rays

C. 4 MeV X-rays

D. 8 MeV X-rays

 

Answer is D: Penetrating ability of electromagnetic radiation increases as energy does.

 

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26. Exposing a foetus or young baby to X-rays should be avoided. What is the cause of the danger most likely to be due to?

A. Denaturing of cells due to the increase in temperature in cells absorbing radiation.

B. Damage to a cell’s DNA.

C. The baby becoming radioactive.

D. The formation of a blood clot.

 

Answer is B: X-rays are ionising radiation. This means that ions may be formed from the atoms that make up DNA. In this case, the chemical bonds between atoms will be broken and the molecule will be changed.

 

27. Which of the following is NOT a feature of mammography?

 A. A low accelerating voltage is used for the X-ray tube.

B. Non-ionising radiation is used.

C. The radiation dose is small (<1 mSv).

D. The X-ray tube utilises a molybdenum target.

Answer is B: Mammography uses X-rays which are ionising radiation, albeit giving the patient a small dose of radiation.

 

28. Which anatomical plane is usually displayed in a CT scan?

A. Transverse

B. Sagittal

C. Coronal

D. Longitudinal section

 

Answer is A: A cross-section or transverse slice is the usual image viewed. CT images are displayed as if viewed from the direction of the feet.

 

29. Why does an interventional cardiac angiography procedure have the potential to deliver a high dose of radiation to the patient?

A. A radioactive tracer is injected into the patient.

B. An extensive region of the torso is irradiated.

C. Cardiac angiography employs ionising radiation.

D. The X-ray generator is switched on for 10s to 100s of seconds.

 

Answer is D: The long exposure time is the potential problem. All X-ray imaging uses ionising radiation. A radioactive material is not used in cardiac angiography.

 

30. What does the term “ionising radiation” refer to?

A. Any long wavelength electromagnetic radiation

B. Radiation that is emitted by ions

C. Ultrasound radiation

D. Radiation that produces ions when it interacts with matter

 

Answer is D: If ions are produced when radiation passes through a material, it is termed ionising radiation. It also means that energy is deposited within that material.

 

31. When a mammography X-ray tube with an Mo target (characteristic X-ray at 19.6 keV) with an Mo filter is operated at an accelerating voltage of 28 kV, what may be said of the resulting spectrum?

A. The maximum energy that an X-ray photon can have will be 28 keV.

B. Most of the X-rays will have an energy of 19.6 keV.

C. All of the X-ray photons will have an energy of 28 keV.

D. The X-ray beam will contain photons with every energy from 0 keV up to 28 keV.

 

Answer is B: The Mo filter has the effect of stopping photons with energy between 20 and 28 keV. Characteristic X-rays are present with much greater intensity than photons in the rest of the spectrum. So the majority of photons will have energy of about 19 keV. This is the best energy for imaging the compressed breast.

 

32. Why will many X-ray photons pass through the human body without deflection?

A. The carbon, hydrogen and oxygen atoms are transparent to X-rays.

B. The Compton interaction does not occur at diagnostic X-ray energies.

C. The wavelength of X-rays is too long to interact with an object with the dimensions of the human body.

D. The wavelength of X-rays is too short to interact with many atoms.

 

Answer is D: X-ray photons are very small and atoms are mostly empty space. Furthermore they are uncharged so are not attracted to or repelled from electrons and protons. To interact, an X-ray photon must pass extremely close to the nucleus an electron. Hence most pass straight through.

 

33. If the filtration of an X-ray beam is increased from 2 mm aluminium to 5 mm aluminium, how will the intensity of the X-ray spectrum change?

A. It will decrease equally at all frequencies.

B. It will decrease more at lower frequencies than at higher frequencies.

C. It will decrease more at higher frequencies than at lower frequencies.

D. It will decrease only at lower frequencies.

 

Answer is B: Intensity will certainly decrease. The lower frequencies are “less penetrating” than higher frequencies and so are more easily stopped than the higher frequencies.

 

34. What is a difference between X-rays and gamma rays?

A. X-rays emerge from a radioactive atomic nucleus whereas gamma rays are produced in an electrical machine.

B. Gamma rays can be turned off by switching the power supply off.

C. X-rays are produced in an electrical machine, whereas gamma rays emerge from an atomic nucleus.

D. X-rays can penetrate deeper into solid material than can gamma rays.

 

Answer is C: When the electrical supply is turned off, no more X-rays are produced. Gamma rays continue to emanate naturally from a radioactive substance until all the

atoms have decayed.

 

35. What is the maximum energy that an X-ray tube energised to 140 kV will accelerate electrons to?

A. 140 eV

B. 140 keV

C. 140 J

D. 140,000 keV

 

Answer is B: The unit “electron volt” is the amount of energy gained by an electron when it is accelerated by a potential difference of 1 V. 140 keV is the amount of energy gained by an electron when it is accelerated by a potential difference of 140 kV.

 

36. Why is an X-ray beam passed through a metal foil (i.e. filtered) before irradiation a patient? To: 

A. Remove electrons from the X-ray beam

B. Prevent high-energy photons entering the patient

C. Increase the mean energy of the beam

D. Increase the ratio of low energy photons to high energy photons

 

Answer is C: The filter material will remove the lowest energy X-ray photons from the beam. As a result, it will also increase the mean energy of the beam.

 

37. What is the purpose of an intensifying screen when used to view an X-ray image?

A. It converts a small number of X-ray photons into a large number of visible light photons.

B. It converts low-energy X-ray photons into high-energy visible light photons.

C. It improves the absorption efficiency of X-rays.

D. It improves the conversion efficiency of the detector.

 

Answer is A: An X-ray photon has much higher energy than a visible photon; hence, one X-ray photon has sufficient energy to produce a great many visible photons. Furthermore, visible light can be seen by human eyes but X-rays cannot. Such screens mean that a lower radiation dose can be given to the patient while still producing a useful image.

 

38. Which element is NOT used in the construction of the anode of an X-ray tube?

A. Rhenium

B. Tungsten

C. Aluminium

D. Molybdenum

 

Answer is C: Aluminum (atomic number 13) is too light to be used in an X-ray tube anode. It is however used as a filter to remove low-frequency X-rays from the beam.

 

39. In which one of the following situations are characteristic X-rays produced?

A. When an outer shell electron is knocked out of the atom and the vacancy is filled by another electron.

B. When electrons bombarding the atom have less than 20 keV of energy.

C. When the bombarding electrons have LESS energy than the binding energy of the K shell.

D. When a K shell electron is knocked out of a target atom and the vacancy is filled by an outer electron.

 

Answer is D: Electron shells are labelled K, L, M, etc. from innermost to outermost shell. Electrons in the K shell, being closer, are most tightly bound to the nucleus and require more energy to be knocked out of the atom. When the hole left behind is filled by another electron, it gives up some of its energy as a characteristic X-ray photon.

 

40. The binding energy of an electron in the K shell of a molybdenum atom is 20.0 keV. Given that one of the characteristic X-rays of molybdenum atom is 17.8 keV, what is the binding energy of the other electron energy level?

A. 37.9 keV

B. 20.0 keV

C. 17.8 keV

D. 2.2 keV

 

Answer is D: Electrons in the K shell are the most tightly bound and so have the most binding energy. That is, 20 keV is the most energetic characteristic X-ray for Mo. If 17.8 keV is a characteristic X-ray, then there must be an energy difference of 17.8 keV between the 20.0 keV level and the one we want. 20–17.8 = 2.2 keV.

 

41. Why is the anode surface of an X-ray tube is inclined at an angle to the bombarding electron beam? So that:

A. The X-ray beam is directed towards the exit window.

B. The effective focal spot is smaller than the actual focal spot.

C. A diverging X-ray beam is produced.

D. The emerging beam is parallel.

 

Answer is B: A small focal spot will produce a sharper X-ray image. A small focal spot will also mean a large amount of heat is deposited in that part of the anode. Inclining the anode angle to about 7° will spread the bombarding electrons onto a larger area, while making the size of the emerging X-ray beam narrower.

 

42. The bremsstrahlung interaction produces all of the following except one. Which one?

A. Characteristic radiation

B. Heat in the anode

C. A bombarding electron with less kinetic energy

D. Photons with a range of energies

 

Answer is A: Bremsstrahlung radiation is emitted when a fast-moving electron is slowed down by passing close to a nucleus in the target anode. Characteristic radiation is emitted when an electron bombarding the anode collides with a K shell electron and knocks it out of the atom.

 

43. The benefit of having a small focal spot on the anode of an X-ray tube is that:

A. Scattered radiation is minimised.

B. Heat production in the anode is minimised.

C. The resulting image will be sharply defined.

D. The anodes may be made smaller.

 

Answer is C: A small focal spot ensures that the produced X-rays come from close to a “point” source. Such a source will produce an X-ray image with very little “penumbra”, that is, the image will be sharper.

 

44. Given that the absorption of photons by the photoelectric effect increases with the Z of the absorbing atom and decreases with energy of the photon, which of the following is likely to be true?

A. The photoelectric effect is of greater importance in soft tissue than in bone.

B. The photoelectric effect is of greater importance in bone than in soft tissue.

C. There is no marked difference in the occurrence of the photoelectric effect in soft tissue than in bone.

D. Photons with energy greater than 60 keV are more likely to undergo the photoelectric effect than photons of energy less than 60 keV.

 

Answer is B: Bone contains Ca and P which have atomic numbers of 20 and 15, respectively. The elements C, H and O which predominate in soft tissue have the lower Z values of 6, 1 and 8, respectively. Hence, the photoelectric interaction is more common in bone.

 

45. What is the “heel effect” that is displayed in an X-ray spectrum is due to?

A. Poor collimation

B. Absorption of X-rays as they pass out of the anode

C. The use of wedge filters in the X-ray beam

D. Operating the X-ray tube with the beam horizontal

 

Answer is B: X-ray photons are produced at different depths within the anode. Hence, they traverse different distances through the anode before they emerge. This ensures that those traversing the greatest distance suffer the greater absorbance. So a noticeable modification to the spectrum (a “heel”) with angle from the anode is discernible.

 

46. The photoelectric effect produces all of the following except one. Which one?

A. Characteristic radiation (a secondary X-ray photon)

B. A scattered X-ray photon

C. An energetic photoelectron

D. A dose of radiation to tissue

 

Answer is B: An incoming photon with sufficient energy is totally absorbed by an electron which is then ejected from the atom as a “photoelectron”. As the energy of the incoming photon is all absorbed, there is not scattered photon.

 

47. Consider 100 X-ray photons (all of the same energy) that are fired at a 4 mm thick sheet of aluminum and that 80 pass through without interacting. What is the linear attenuation coefficient (in cm1) for Al at this energy?

A. 0.2 cm1

B. 0.5 cm1

C. 2.0 cm1

D. 5.0 cm

Answer is B: 80 out of 100 photons (80%) pass through. Thus, 20% are stopped. Hence, 20% per 4 mm, or 5% per 1 mm is = 0.05 mm1 = 0.5 cm1 as there are 10 mm per cm.

 

48. An X-ray beam with a high HVL (half-value layer) is:

A. Said to be “softer” than a beam of low HVL

B. Less penetrating than a beam of low HVL

C. Likely to produce a larger absorbed dose to the skin

D. More penetrating than a beam of low HVL

 

Answer is D: Having a HVL of “x” mmAl means that half of the photons in the beam are able to penetrate “x” mmAl. Hence, the higher is the HVL, the more penetrating is the beam. Also it will be said to be “harder” and to produce a lower absorbed dose to tissue.

 

49. Which statement about the Compton effect is NOT correct?

A. A Compton interaction is more likely in bone than in muscle tissue.

B. The deflected photon has less energy than the original photon.

C. An electron is ejected from the atom.

D. Compton events contribute to scattered radiation.

 

Answer is A: A Compton interaction occurs when a photon uses some of its energy to eject an electron, while the remaining energy becomes a scattered photon. The probability that an X-ray photon will undergo a Compton interaction depends on the density of the issue and the energy of the photon. Tissues such as muscle, blood and solid organs create the greatest amount of scatter radiation in the body. Bone tends to absorb more of X-rays.

 

50. Use the “inverse square law” to compare to being 1 m from an X-ray source, with the photon flux at a distance of 3 m from the source. The flux will be:

A. Nine times as great

B. Six times as great

C. One sixth as great

D. One ninth as great

 

Answer is D: “Inverse square” means at double the distance, the flux will be reduced to one half squared of the original flux (½)2 = ¼. At 3× the distance, the flux will be (1/3)2 = 1/9.

 

51. Imagine that the X-radiation from a diagnostic machine was measured by a dose-area-product meter that could count individual photons. For a particular exposure, 8 × 1012 photons were collimated to pass through a 10 cm × 10 cm aperture at 1 m from the X-ray source. What would be the number of photons passing through a 20 cm × 20 cm aperture at 2 m from the X-ray source?

 A. 8 × 1012 photons

B. 2 × 1012 photons

C. 16 × 1012 photons

D. 4 × 1012 photons

 

Answer is A: By the inverse square law, a 10 cm × 10 cm beam at 1 m from the source would diverge to a 20 cm × 20 cm beam at 2 m from the source (that is to four times the area). However, the same number of photons would be passing through this wider area.

 

52. Why are iodine and barium ideal for use as contrast agents in imaging of soft tissue?

A. They are high Z atoms so the probability of a Compton scatter is high.

B. The binding energy of their K shell is in the middle of the diagnostic energy range.

C. The energy of their characteristic X-rays is in the middle of the diagnostic energy range.

D. They are high Z atoms so the probability of a photoelectric interaction is high.

 

Answer is B: As the binding energy of their K shell is in the middle of the diagnostic energy range, many X-ray photons will be absorbed by I and Ba. Hence, organs containing these elements will appear white on the image and so will contrast with the grey shades of the surrounding soft tissue.

 

53. One difference between the X-radiation in the primary beam and the scattered radiation is that: 

A. Scattered radiation contributes dose to the surroundings, primary beam does not.

B. Scattered radiation is more penetrating than the primary beam.

C. Scattered radiation is not absorbed by the patient while photons in the primary beam are.

D. Primary X-ray photons that have passed through the patient contribute to patient dose.

 

Answer is A: Scattered radiation has had its direction of travel altered and so may irradiate people standing nearby. Scattered radiation is less penetrating than the primary beam and may be absorbed by the patient and so contribute to their radiation dose. Choice D is wrong as emerging photons do not contribute to dose.

 

54. The detectors in a CT scanner measure which one of the following?

A. The linear attenuation coefficient of each pixel

B. The grey scale value of the image

C. The Hounsfield unit of each pixel

D. The average linear attenuation coefficient

 

Answer is D: The average linear attenuation coefficient along the path from where the beam enters the patient’s body to where it emerges. This number is then attributed to every pixel along the path. A variety of techniques is then used to create a cross-sectional image of anatomy and to assign a “Hounsfield unit” to each pixel of the image.

 

55. If a CT (Hounsfield) number associated with a given tissue is close to zero, then what is the tissue likely to be? 

A. Mostly water

B. Predominantly lung

C. Mainly muscle

D. It probably contains bone

 

Answer is A: The numerator of Hounsfield number is calculated by subtracting the “linear attenuation coefficient” of water from the attenuation coefficient of the tissue. If the tissue coefficient is close to that of water, the result will be close to zero.


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